acwing::acwing854_408 命名空间参考

1. Floyd求最短路

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函数
int	main (istream &cin, ostream &cout)
	TEST (acwing854_408, case1)

详细描述

1. Floyd求最短路

函数说明

main()

int acwing::acwing854_408::main	(	istream &	cin,
		ostream &	cout
	)

在文件 acwing408.cpp 第 808 行定义.

                                              {
            int n, m, k;
            cin >> n >> m >> k;
            vector<vector<int>> g = vector<vector<int>>(n + 1, vector<int>(n + 1, INT_MAX));
            for(int i = 1; i <= n; i++) {
                g[i][i] = 0;
            }
            while(m--) {
                int x, y, z;
                cin >> x >> y >> z;
                g[x][y] = min(g[x][y], z);
            }
            for(int k = 1; k <= n; k++) {
                for(int i = 1; i <= n; i++) {
                    for(int j = 1; j <= n; j++) {
                        if(g[i][k] != INT_MAX && g[k][j] != INT_MAX) {
                            g[i][j] = min(g[i][j], g[i][k] + g[k][j]);
                        }
                    }
                }
            }
            while(k--) {
                int x, y;
                cin >> x >> y;
                if(g[x][y] == INT_MAX) {
                    cout << "impossible" << endl;
                } else {
                    cout << g[x][y] << endl;
                }
            }
            return 0;
        }

被这些函数引用 TEST().

TEST()

acwing::acwing854_408::TEST	(	acwing854_408	,
		case1
	)

在文件 acwing408_test.cpp 第 1184 行定义.

                                   {
            istringstream in("3 3 2\n"
                             "1 2 1\n"
                             "2 3 2\n"
                             "1 3 1\n"
                             "2 1\n"
                             "1 3");
            auto out = ostringstream();
            main(in, out);
            const auto ans = out.str();
            ASSERT_EQ("impossible\n"
                      "1\n",
                      ans);
        }

引用了 main().