1015 Reversible Primes
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unsigned | get_num (const string &n, unsigned d) |
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unsigned | get_num (const string &n, unsigned int d) |
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bool | is_prime (unsigned int n) |
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bool | is_prime (unsigned n) |
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int | main (istream &cin, ostream &cout) |
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unsigned | reverse (unsigned int n, unsigned int d) |
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unsigned | reverse (unsigned n, unsigned d) |
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| TEST (a1015, case1) |
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◆ get_num() [1/2]
unsigned pat::a::a1015::get_num |
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const string & | n, |
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unsigned | d ) |
◆ get_num() [2/2]
unsigned pat::a::a1015::get_num |
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const string & | n, |
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unsigned int | d ) |
在文件 pat.cpp 第 4413 行定义.
4413 {
4414 unsigned ans = 0;
4415 for(const char ch: n) {
4416 ans *= d;
4417 ans += ch - '0';
4418 }
4419 return ans;
4420 }
被这些函数引用 reverse().
◆ is_prime() [1/2]
bool pat::a::a1015::is_prime |
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unsigned int | n | ) |
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在文件 pat.cpp 第 4422 行定义.
4422 {
4423 if(n < 2) {
4424 return false;
4425 }
4426 for(unsigned i = 2; i <= sqrt(n); i++) {
4427 if(n % i == 0) {
4428 return false;
4429 }
4430 }
4431 return true;
4432 }
被这些函数引用 main().
◆ is_prime() [2/2]
bool pat::a::a1015::is_prime |
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unsigned | n | ) |
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◆ main()
int pat::a::a1015::main |
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istream & | cin, |
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ostream & | cout ) |
在文件 pat.cpp 第 4399 行定义.
4399 {
4400 unsigned n;
4401 unsigned d;
4402 while(cin >> n && cin >> d) {
4404 cout << "Yes";
4405 } else {
4406 cout << "No";
4407 }
4408 cout << endl;
4409 }
4410 return 0;
4411 }
unsigned reverse(unsigned int n, unsigned int d)
bool is_prime(unsigned int n)
引用了 is_prime() , 以及 reverse().
被这些函数引用 TEST().
◆ reverse() [1/2]
unsigned pat::a::a1015::reverse |
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unsigned int | n, |
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unsigned int | d ) |
在文件 pat.cpp 第 4434 行定义.
4434 {
4435 ostringstream oss;
4436 while(n != 0) {
4437 oss << n % d;
4438 n /= d;
4439 }
4441 }
unsigned get_num(const string &n, unsigned int d)
引用了 get_num().
被这些函数引用 main().
◆ reverse() [2/2]
unsigned pat::a::a1015::reverse |
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unsigned | n, |
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unsigned | d ) |
◆ TEST()
pat::a::a1015::TEST |
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a1015 | , |
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case1 | ) |
在文件 pat_test.cpp 第 2075 行定义.
2075 {
2076 istringstream in("73 10\n"
2077 "23 2\n"
2078 "23 10\n"
2079 "-2");
2080 auto out = ostringstream();
2082 ASSERT_EQ("Yes\n"
2083 "Yes\n"
2084 "No\n",
2085 out.str());
2086 }
int main(istream &cin, ostream &cout)
引用了 main().