pat::b::b1095 命名空间参考

1095 解码PAT准考证 更多...

类
struct	p_stu_comp
struct	room
struct	room_cnt_comp
struct	student

函数
int	main (istream &cin, ostream &cout)
	TEST (b1095, case1)

详细描述

1095 解码PAT准考证

函数说明

main()

int pat::b::b1095::main	(	istream &	cin,
		ostream &	cout
	)

在文件 pat.cpp 第 3327 行定义.

                                                  {
                int n;
                int m;
                cin >> n >> m;
                unordered_map<string, room> rooms;
                unordered_map<char, unordered_set<student *>> levels;
                unordered_map<string, unordered_map<string, int>> dates;
                for(int i = 0; i < n; i++) {
                    auto *stu = new student();
                    cin >> stu->id >> stu->grade;
                    stu->level = stu->id[0];
                    stu->room  = stu->id.substr(1, 3);
                    stu->date  = stu->id.substr(4, 6);
                    rooms[stu->room].sum += stu->grade;
                    rooms[stu->room].count++;
                    levels[stu->level].insert(stu);
                    dates[stu->date][stu->room]++;
                }
                for(int i = 0; i < m; i++) {
                    int typ;
                    cin >> typ;
                    cout << "Case " << i + 1 << ": " << typ << ' ';
                    if(typ == 1) {
                        char l;
                        cin >> l;
                        cout << l << endl;
                        if(static_cast<unsigned int>(levels.contains(l)) != 0U) {
                            vector<student *> vec;
                            for(auto *const pstu: levels[l]) {
                                vec.emplace_back(pstu);
                            }
                            sort(vec.begin(), vec.end(), p_stu_comp());
                            for(auto *stu: vec) {
                                cout << stu->id << ' ' << stu->grade << endl;
                            }
                        } else {
                            cout << "NA" << endl;
                        }
                    } else if(typ == 2) {
                        string room_id;
                        cin >> room_id;
                        cout << room_id << endl;
                        if(static_cast<unsigned int>(rooms.contains(room_id)) != 0U) {
                            cout << rooms[room_id].count << ' ' << rooms[room_id].sum << endl;
                        } else {
                            cout << "NA" << endl;
                        }
                    } else if(typ == 3) {
                        string date;
                        cin >> date;
                        cout << date << endl;
                        if(dates[date].empty()) {
                            cout << "NA" << endl;
                            continue;
                        }
                        vector<pair<string, int>> vec;
                        for(const auto &room_cnt: dates[date]) {
                            vec.emplace_back(room_cnt);
                        }
                        sort(vec.begin(), vec.end(), room_cnt_comp());
                        for(const auto &[id, cnt]: vec) {
                            cout << id << ' ' << cnt << endl;
                        }
                    } else {
                        string op;
                        cout << op << endl;
                        cout << "NA" << endl;
                    }
                }
                return 0;
            }

引用了 pat::a::a7_2::vec.

被这些函数引用 TEST().

TEST()

pat::b::b1095::TEST	(	b1095	,
		case1
	)

在文件 pat_test.cpp 第 1645 行定义.

                               {
                istringstream in("8 4\n"
                                 "B123180908127 99\n"
                                 "B102180908003 86\n"
                                 "A112180318002 98\n"
                                 "T107150310127 62\n"
                                 "A107180908108 100\n"
                                 "T123180908010 78\n"
                                 "B112160918035 88\n"
                                 "A107180908021 98\n"
                                 "1 A\n"
                                 "2 107\n"
                                 "3 180908\n"
                                 "2 999");
                auto out = ostringstream();
                main(in, out);
                const auto ans = out.str();
                ASSERT_EQ("Case 1: 1 A\n"
                          "A107180908108 100\n"
                          "A107180908021 98\n"
                          "A112180318002 98\n"
                          "Case 2: 2 107\n"
                          "3 260\n"
                          "Case 3: 3 180908\n"
                          "107 2\n"
                          "123 2\n"
                          "102 1\n"
                          "Case 4: 2 999\n"
                          "NA\n",
                          out.str());
            }

引用了 main().