pat::b::b1080 命名空间参考

1080 MOOC期终成绩 更多...

类
struct	student

函数
int	main (istream &cin, ostream &cout)
	TEST (b1080, case1)

详细描述

1080 MOOC期终成绩

函数说明

main()

int pat::b::b1080::main	(	istream &	cin,
		ostream &	cout )

在文件 pat.cpp 第 2800 行定义.

                                                  {
                int p;
                int m;
                int n;
                cin >> p >> m >> n;
                unordered_map<string, student> um;
                for(int i = 0; i < p; i++) {
                    string id;
                    cin >> id >> um[id].p;
                }
                for(int i = 0; i < m; i++) {
                    string id;
                    cin >> id >> um[id].mid_term;
                }
                for(int i = 0; i < n; i++) {
                    string id;
                    cin >> id >> um[id].final;
                }
                vector<student> vec;
                for(auto &[id, stu]: um) {
                    stu.id    = id;
                    stu.score = stu.get_score();
                    if(stu.p >= 200 && stu.score >= 60) {
                        vec.push_back(stu);
                    }
                }
                sort(vec.begin(), vec.end());
                for(const auto &stu: vec) {
                    cout << stu.id << ' ' << stu.p << ' ' << stu.mid_term << ' ' << stu.final << ' ' << stu.score << endl;
                }
                return 0;
            }

被这些函数引用 TEST().

TEST()

pat::b::b1080::TEST	(	b1080	,
		case1	)

在文件 pat_test.cpp 第 1378 行定义.

                               {
                istringstream in("6 6 7\n"
                                 "01234 880\n"
                                 "a1903 199\n"
                                 "ydjh2 200\n"
                                 "wehu8 300\n"
                                 "dx86w 220\n"
                                 "missing 400\n"
                                 "ydhfu77 99\n"
                                 "wehu8 55\n"
                                 "ydjh2 98\n"
                                 "dx86w 88\n"
                                 "a1903 86\n"
                                 "01234 39\n"
                                 "ydhfu77 88\n"
                                 "a1903 66\n"
                                 "01234 58\n"
                                 "wehu8 84\n"
                                 "ydjh2 82\n"
                                 "missing 99\n"
                                 "dx86w 81");
                auto out = ostringstream();
                main(in, out);
                const auto ans = out.str();
                ASSERT_EQ("missing 400 -1 99 99\n"
                          "ydjh2 200 98 82 88\n"
                          "dx86w 220 88 81 84\n"
                          "wehu8 300 55 84 84\n",
                          out.str());
            }

引用了 main().